0=x^2-41x+210

Solution for 0=x^2-41x+210 equation:

0=x^2-41x+210

We move all terms to the left:

0-(x^2-41x+210)=0

We add all the numbers together, and all the variables

-(x^2-41x+210)=0

We get rid of parentheses

-x^2+41x-210=0

We add all the numbers together, and all the variables

-1x^2+41x-210=0

a = -1; b = 41; c = -210;
Δ = b2-4ac
Δ = 412-4·(-1)·(-210)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-29}{2*-1}=\frac{-70}{-2}
=+35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+29}{2*-1}=\frac{-12}{-2}
=+6
$